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-u+\frac{4}{5}+\frac{1}{3}u=-\frac{1}{3}
Add \frac{1}{3}u to both sides.
-u+\frac{1}{3}u=-\frac{1}{3}-\frac{4}{5}
Subtract \frac{4}{5} from both sides.
-u+\frac{1}{3}u=-\frac{5}{15}-\frac{12}{15}
Least common multiple of 3 and 5 is 15. Convert -\frac{1}{3} and \frac{4}{5} to fractions with denominator 15.
-u+\frac{1}{3}u=\frac{-5-12}{15}
Since -\frac{5}{15} and \frac{12}{15} have the same denominator, subtract them by subtracting their numerators.
-u+\frac{1}{3}u=-\frac{17}{15}
Subtract 12 from -5 to get -17.
-\frac{2}{3}u=-\frac{17}{15}
Combine -u and \frac{1}{3}u to get -\frac{2}{3}u.
u=-\frac{17}{15}\left(-\frac{3}{2}\right)
Multiply both sides by -\frac{3}{2}, the reciprocal of -\frac{2}{3}.
u=\frac{-17\left(-3\right)}{15\times 2}
Multiply -\frac{17}{15} times -\frac{3}{2} by multiplying numerator times numerator and denominator times denominator.
u=\frac{51}{30}
Do the multiplications in the fraction \frac{-17\left(-3\right)}{15\times 2}.
u=\frac{17}{10}
Reduce the fraction \frac{51}{30} to lowest terms by extracting and canceling out 3.