Solve -b^2+8(-6)+4

$$- b ^ { 2 } + 8 ( - 6 ) + 4$$

Evaluate

$$-b^{2}-44$$

Solution Steps

Multiply 8 and -6 to get -48.

$$-b^{2}-48+4$$

Add -48 and 4 to get -44.

$$-b^{2}-44$$

Differentiate w.r.t. b

$$-2b$$

Steps Using Derivative Rule for Sum

Multiply 8 and -6 to get -48.

$$\frac{\mathrm{d}}{\mathrm{d}b}(-b^{2}-48+4)$$

Add -48 and 4 to get -44.

$$\frac{\mathrm{d}}{\mathrm{d}b}(-b^{2}-44)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$2\left(-1\right)b^{2-1}$$

Multiply 2 times -1.

$$-2b^{2-1}$$

Subtract 1 from 2.

$$-2b^{1}$$

For any term t, t^{1}=t.

$$-2b$$