Solve -96x+1/2=03

$$- 96 x + \frac { 1 } { 2 } = 03$$

Solve for x

$$x=\frac{1}{192}\approx 0.005208333$$

Steps for Solving Linear Equation

Multiply 0 and 3 to get 0.

$$-96x+\frac{1}{2}=0$$

Subtract \frac{1}{2} from both sides. Anything subtracted from zero gives its negation.

$$-96x=-\frac{1}{2}$$

Divide both sides by -96.

$$x=\frac{-\frac{1}{2}}{-96}$$

Express \frac{-\frac{1}{2}}{-96} as a single fraction.

$$x=\frac{-1}{2\left(-96\right)}$$

Multiply 2 and -96 to get -192.

$$x=\frac{-1}{-192}$$

Fraction \frac{-1}{-192} can be simplified to \frac{1}{192} by removing the negative sign from both the numerator and the denominator.

$$x=\frac{1}{192}$$