Solve -8x^2-2=-10

$$- 8 x ^ { 2 } - 2 = - 10$$

Solve for x

$$x=1$$

$$x=-1$$

Steps by Finding Square Root

Add 2 to both sides.

$$-8x^{2}=-10+2$$

Add -10 and 2 to get -8.

$$-8x^{2}=-8$$

Divide both sides by -8.

$$x^{2}=\frac{-8}{-8}$$

Divide -8 by -8 to get 1.

$$x^{2}=1$$

Take the square root of both sides of the equation.

$$x=1 x=-1$$

Steps Using the Quadratic Formula

Add 10 to both sides.

$$-8x^{2}-2+10=0$$

Add -2 and 10 to get 8.

$$-8x^{2}+8=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute -8 for a, 0 for b, and 8 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-8\right)\times 8}}{2\left(-8\right)}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-8\right)\times 8}}{2\left(-8\right)}$$

Multiply -4 times -8.

$$x=\frac{0±\sqrt{32\times 8}}{2\left(-8\right)}$$

Multiply 32 times 8.

$$x=\frac{0±\sqrt{256}}{2\left(-8\right)}$$

Take the square root of 256.

$$x=\frac{0±16}{2\left(-8\right)}$$

Multiply 2 times -8.

$$x=\frac{0±16}{-16}$$

Now solve the equation x=\frac{0±16}{-16} when ± is plus. Divide 16 by -16.

$$x=-1$$

Now solve the equation x=\frac{0±16}{-16} when ± is minus. Divide -16 by -16.

$$x=1$$

The equation is now solved.

$$x=-1 x=1$$