Solve for x
x=\frac{6\left(y+3\right)}{7}
Solve for y
y=\frac{7x}{6}-3
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-7x=-18-6y
Subtract 6y from both sides.
-7x=-6y-18
The equation is in standard form.
\frac{-7x}{-7}=\frac{-6y-18}{-7}
Divide both sides by -7.
x=\frac{-6y-18}{-7}
Dividing by -7 undoes the multiplication by -7.
x=\frac{6y+18}{7}
Divide -18-6y by -7.
6y=-18+7x
Add 7x to both sides.
6y=7x-18
The equation is in standard form.
\frac{6y}{6}=\frac{7x-18}{6}
Divide both sides by 6.
y=\frac{7x-18}{6}
Dividing by 6 undoes the multiplication by 6.
y=\frac{7x}{6}-3
Divide -18+7x by 6.
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