Solve -7+-3-1/3/-2+frac{1{3}}

$$- 7 + \frac { - 3 - \frac { 1 } { 3 } } { - 2 + \frac { 1 } { 3 } }$$

Evaluate

$$-5$$

Solution Steps

Convert -3 to fraction -\frac{9}{3}.

$$-7+\frac{-\frac{9}{3}-\frac{1}{3}}{-2+\frac{1}{3}}$$

Since -\frac{9}{3} and \frac{1}{3} have the same denominator, subtract them by subtracting their numerators.

$$-7+\frac{\frac{-9-1}{3}}{-2+\frac{1}{3}}$$

Subtract 1 from -9 to get -10.

$$-7+\frac{-\frac{10}{3}}{-2+\frac{1}{3}}$$

Convert -2 to fraction -\frac{6}{3}.

$$-7+\frac{-\frac{10}{3}}{-\frac{6}{3}+\frac{1}{3}}$$

Since -\frac{6}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$-7+\frac{-\frac{10}{3}}{\frac{-6+1}{3}}$$

Add -6 and 1 to get -5.

$$-7+\frac{-\frac{10}{3}}{-\frac{5}{3}}$$

Divide -\frac{10}{3} by -\frac{5}{3} by multiplying -\frac{10}{3} by the reciprocal of -\frac{5}{3}.

$$-7-\frac{10}{3}\left(-\frac{3}{5}\right)$$

Multiply -\frac{10}{3} times -\frac{3}{5} by multiplying numerator times numerator and denominator times denominator.

$$-7+\frac{-10\left(-3\right)}{3\times 5}$$

Do the multiplications in the fraction \frac{-10\left(-3\right)}{3\times 5}.

$$-7+\frac{30}{15}$$

Divide 30 by 15 to get 2.

$$-7+2$$

Add -7 and 2 to get -5.

$$-5$$

Factor

$$-5$$