Solve -6-|-0.6|+(-5)+3/5

$$- 6 - | - 0.6 | + ( - 5 ) + \frac { 3 } { 5 }$$

Evaluate

$$-11$$

Solution Steps

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -0.6 is 0.6.

$$-6-0.6-5+\frac{3}{5}$$

Subtract 0.6 from -6 to get -6.6.

$$-6.6-5+\frac{3}{5}$$

Subtract 5 from -6.6 to get -11.6.

$$-11.6+\frac{3}{5}$$

Convert decimal number -11.6 to fraction -\frac{116}{10}. Reduce the fraction -\frac{116}{10} to lowest terms by extracting and canceling out 2.

$$-\frac{58}{5}+\frac{3}{5}$$

Since -\frac{58}{5} and \frac{3}{5} have the same denominator, add them by adding their numerators.

$$\frac{-58+3}{5}$$

Add -58 and 3 to get -55.

$$\frac{-55}{5}$$

Divide -55 by 5 to get -11.

$$-11$$

Factor

$$-11$$