Solve -6*4-9*3+5*2+x-10

$$- 6 \times 4 - 9 \times 3 + 5 \times 2 + x - 10$$

Evaluate

$$x-51$$

Solution Steps

Multiply -6 and 4 to get -24.

$$-24-9\times 3+5\times 2+x-10$$

Multiply 9 and 3 to get 27.

$$-24-27+5\times 2+x-10$$

Subtract 27 from -24 to get -51.

$$-51+5\times 2+x-10$$

Multiply 5 and 2 to get 10.

$$-51+10+x-10$$

Add -51 and 10 to get -41.

$$-41+x-10$$

Subtract 10 from -41 to get -51.

$$-51+x$$

Differentiate w.r.t. x

$$1$$

Steps Using Derivative Rule for Sum

Multiply -6 and 4 to get -24.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-24-9\times 3+5\times 2+x-10)$$

Multiply 9 and 3 to get 27.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-24-27+5\times 2+x-10)$$

Subtract 27 from -24 to get -51.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-51+5\times 2+x-10)$$

Multiply 5 and 2 to get 10.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-51+10+x-10)$$

Add -51 and 10 to get -41.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-41+x-10)$$

Subtract 10 from -41 to get -51.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-51+x)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$x^{1-1}$$

Subtract 1 from 1.

$$x^{0}$$

For any term t except 0, t^{0}=1.

$$1$$