Solve -6+3(6-2)(7-9)^2-1/2(-12-18)

$$- 6 + 3 ( 6 - 2 ) ( 7 - 9 ) ^ { 2 } - \frac { 1 } { 2 } ( - 12 - 18 )$$

Evaluate

$$57$$

Solution Steps

Subtract 2 from 6 to get 4.

$$-6+3\times 4\left(7-9\right)^{2}-\frac{1}{2}\left(-12-18\right)$$

Multiply 3 and 4 to get 12.

$$-6+12\left(7-9\right)^{2}-\frac{1}{2}\left(-12-18\right)$$

Subtract 9 from 7 to get -2.

$$-6+12\left(-2\right)^{2}-\frac{1}{2}\left(-12-18\right)$$

Calculate -2 to the power of 2 and get 4.

$$-6+12\times 4-\frac{1}{2}\left(-12-18\right)$$

Multiply 12 and 4 to get 48.

$$-6+48-\frac{1}{2}\left(-12-18\right)$$

Add -6 and 48 to get 42.

$$42-\frac{1}{2}\left(-12-18\right)$$

Subtract 18 from -12 to get -30.

$$42-\frac{1}{2}\left(-30\right)$$

Multiply \frac{1}{2} and -30 to get -15.

$$42-\left(-15\right)$$

The opposite of -15 is 15.

$$42+15$$

Add 42 and 15 to get 57.

$$57$$

Factor

$$3\times 19$$