Solve for a
a=\frac{x}{2}
Solve for x
x=2a
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8a=-x+5x
Add 5x to both sides.
8a=4x
Combine -x and 5x to get 4x.
\frac{8a}{8}=\frac{4x}{8}
Divide both sides by 8.
a=\frac{4x}{8}
Dividing by 8 undoes the multiplication by 8.
a=\frac{x}{2}
Divide 4x by 8.
-5x+8a+x=0
Add x to both sides.
-4x+8a=0
Combine -5x and x to get -4x.
-4x=-8a
Subtract 8a from both sides. Anything subtracted from zero gives its negation.
\frac{-4x}{-4}=-\frac{8a}{-4}
Divide both sides by -4.
x=-\frac{8a}{-4}
Dividing by -4 undoes the multiplication by -4.
x=2a
Divide -8a by -4.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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