Solve for x
x=\frac{3\left(y-5\right)}{5}
Solve for y
y=\frac{5\left(x+3\right)}{3}
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-5x=15-3y
Subtract 3y from both sides.
\frac{-5x}{-5}=\frac{15-3y}{-5}
Divide both sides by -5.
x=\frac{15-3y}{-5}
Dividing by -5 undoes the multiplication by -5.
x=\frac{3y}{5}-3
Divide 15-3y by -5.
3y=15+5x
Add 5x to both sides.
3y=5x+15
The equation is in standard form.
\frac{3y}{3}=\frac{5x+15}{3}
Divide both sides by 3.
y=\frac{5x+15}{3}
Dividing by 3 undoes the multiplication by 3.
y=\frac{5x}{3}+5
Divide 15+5x by 3.
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