Solve for x
x=\frac{12y-8}{5}
Solve for y
y=\frac{5x}{12}+\frac{2}{3}
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-5x=8-12y
Subtract 12y from both sides.
\frac{-5x}{-5}=\frac{8-12y}{-5}
Divide both sides by -5.
x=\frac{8-12y}{-5}
Dividing by -5 undoes the multiplication by -5.
x=\frac{12y-8}{5}
Divide 8-12y by -5.
12y=8+5x
Add 5x to both sides.
12y=5x+8
The equation is in standard form.
\frac{12y}{12}=\frac{5x+8}{12}
Divide both sides by 12.
y=\frac{5x+8}{12}
Dividing by 12 undoes the multiplication by 12.
y=\frac{5x}{12}+\frac{2}{3}
Divide 8+5x by 12.
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