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-5p^{2}=-4
Subtract 4 from both sides. Anything subtracted from zero gives its negation.
p^{2}=\frac{-4}{-5}
Divide both sides by -5.
p^{2}=\frac{4}{5}
Fraction \frac{-4}{-5} can be simplified to \frac{4}{5} by removing the negative sign from both the numerator and the denominator.
p=\frac{2\sqrt{5}}{5} p=-\frac{2\sqrt{5}}{5}
Take the square root of both sides of the equation.
-5p^{2}+4=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
p=\frac{0±\sqrt{0^{2}-4\left(-5\right)\times 4}}{2\left(-5\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -5 for a, 0 for b, and 4 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
p=\frac{0±\sqrt{-4\left(-5\right)\times 4}}{2\left(-5\right)}
Square 0.
p=\frac{0±\sqrt{20\times 4}}{2\left(-5\right)}
Multiply -4 times -5.
p=\frac{0±\sqrt{80}}{2\left(-5\right)}
Multiply 20 times 4.
p=\frac{0±4\sqrt{5}}{2\left(-5\right)}
Take the square root of 80.
p=\frac{0±4\sqrt{5}}{-10}
Multiply 2 times -5.
p=-\frac{2\sqrt{5}}{5}
Now solve the equation p=\frac{0±4\sqrt{5}}{-10} when ± is plus.
p=\frac{2\sqrt{5}}{5}
Now solve the equation p=\frac{0±4\sqrt{5}}{-10} when ± is minus.
p=-\frac{2\sqrt{5}}{5} p=\frac{2\sqrt{5}}{5}
The equation is now solved.