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-48x^{2}=-336
Subtract 336 from both sides. Anything subtracted from zero gives its negation.
x^{2}=\frac{-336}{-48}
Divide both sides by -48.
x^{2}=7
Divide -336 by -48 to get 7.
x=\sqrt{7} x=-\sqrt{7}
Take the square root of both sides of the equation.
-48x^{2}+336=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\left(-48\right)\times 336}}{2\left(-48\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -48 for a, 0 for b, and 336 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-48\right)\times 336}}{2\left(-48\right)}
Square 0.
x=\frac{0±\sqrt{192\times 336}}{2\left(-48\right)}
Multiply -4 times -48.
x=\frac{0±\sqrt{64512}}{2\left(-48\right)}
Multiply 192 times 336.
x=\frac{0±96\sqrt{7}}{2\left(-48\right)}
Take the square root of 64512.
x=\frac{0±96\sqrt{7}}{-96}
Multiply 2 times -48.
x=-\sqrt{7}
Now solve the equation x=\frac{0±96\sqrt{7}}{-96} when ± is plus.
x=\sqrt{7}
Now solve the equation x=\frac{0±96\sqrt{7}}{-96} when ± is minus.
x=-\sqrt{7} x=\sqrt{7}
The equation is now solved.