Solve for x
x=\frac{4\left(y+3\right)}{3}
Solve for y
y=\frac{3\left(x-4\right)}{4}
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-3x+12=-4y
Swap sides so that all variable terms are on the left hand side.
-3x=-4y-12
Subtract 12 from both sides.
\frac{-3x}{-3}=\frac{-4y-12}{-3}
Divide both sides by -3.
x=\frac{-4y-12}{-3}
Dividing by -3 undoes the multiplication by -3.
x=\frac{4y}{3}+4
Divide -4y-12 by -3.
-4y=12-3x
The equation is in standard form.
\frac{-4y}{-4}=\frac{12-3x}{-4}
Divide both sides by -4.
y=\frac{12-3x}{-4}
Dividing by -4 undoes the multiplication by -4.
y=\frac{3x}{4}-3
Divide -3x+12 by -4.
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Limits
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