Solve for x
x=-\frac{3y}{4}-3
Solve for y
y=-\frac{4x}{3}-4
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-4x=3y+12
The equation is in standard form.
\frac{-4x}{-4}=\frac{3y+12}{-4}
Divide both sides by -4.
x=\frac{3y+12}{-4}
Dividing by -4 undoes the multiplication by -4.
x=-\frac{3y}{4}-3
Divide 12+3y by -4.
12+3y=-4x
Swap sides so that all variable terms are on the left hand side.
3y=-4x-12
Subtract 12 from both sides.
\frac{3y}{3}=\frac{-4x-12}{3}
Divide both sides by 3.
y=\frac{-4x-12}{3}
Dividing by 3 undoes the multiplication by 3.
y=-\frac{4x}{3}-4
Divide -4x-12 by 3.
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