Solve -4jx(-3)=(-2)*(-5

$$- 4 j x ( - 3 ) = ( - 2 ) \times ( - 5$$

Solve for j

$$j=\frac{5}{6x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Multiply -4 and -3 to get 12.

$$12jx=\left(-2\right)\times \left(-5\right)$$

The equation is in standard form.

$$12xj=10$$

Divide both sides by 12x.

$$\frac{12xj}{12x}=\frac{10}{12x}$$

Dividing by 12x undoes the multiplication by 12x.

$$j=\frac{10}{12x}$$

Divide 10 by 12x.

$$j=\frac{5}{6x}$$

Solve for x

$$x=\frac{5}{6j}$$

$$j\neq 0$$

Steps for Solving Linear Equation

Multiply -4 and -3 to get 12.

$$12jx=\left(-2\right)\times \left(-5\right)$$

The equation is in standard form.

$$12jx=10$$

Divide both sides by 12j.

$$\frac{12jx}{12j}=\frac{10}{12j}$$

Dividing by 12j undoes the multiplication by 12j.

$$x=\frac{10}{12j}$$

Divide 10 by 12j.

$$x=\frac{5}{6j}$$