Solve -4-(-21/2)+3/5-0.5*2-(-1)=

$$- 4 - ( - 2 \frac { 1 } { 2 } ) + \frac { 3 } { 5 } - 0.5 \times 2 - ( - 1 ) =$$

Evaluate

$$-0.9$$

Solution Steps

Multiply 2 and 2 to get 4.

$$-4-\left(-\frac{4+1}{2}\right)+\frac{3}{5}-0.5\times 2-\left(-1\right)$$

Add 4 and 1 to get 5.

$$-4-\left(-\frac{5}{2}\right)+\frac{3}{5}-0.5\times 2-\left(-1\right)$$

The opposite of -\frac{5}{2} is \frac{5}{2}.

$$-4+\frac{5}{2}+\frac{3}{5}-0.5\times 2-\left(-1\right)$$

Convert -4 to fraction -\frac{8}{2}.

$$-\frac{8}{2}+\frac{5}{2}+\frac{3}{5}-0.5\times 2-\left(-1\right)$$

Since -\frac{8}{2} and \frac{5}{2} have the same denominator, add them by adding their numerators.

$$\frac{-8+5}{2}+\frac{3}{5}-0.5\times 2-\left(-1\right)$$

Add -8 and 5 to get -3.

$$-\frac{3}{2}+\frac{3}{5}-0.5\times 2-\left(-1\right)$$

Least common multiple of 2 and 5 is 10. Convert -\frac{3}{2} and \frac{3}{5} to fractions with denominator 10.

$$-\frac{15}{10}+\frac{6}{10}-0.5\times 2-\left(-1\right)$$

Since -\frac{15}{10} and \frac{6}{10} have the same denominator, add them by adding their numerators.

$$\frac{-15+6}{10}-0.5\times 2-\left(-1\right)$$

Add -15 and 6 to get -9.

$$-\frac{9}{10}-0.5\times 2-\left(-1\right)$$

Multiply 0.5 and 2 to get 1.

$$-\frac{9}{10}-1-\left(-1\right)$$

Convert 1 to fraction \frac{10}{10}.

$$-\frac{9}{10}-\frac{10}{10}-\left(-1\right)$$

Since -\frac{9}{10} and \frac{10}{10} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-9-10}{10}-\left(-1\right)$$

Subtract 10 from -9 to get -19.

$$-\frac{19}{10}-\left(-1\right)$$

The opposite of -1 is 1.

$$-\frac{19}{10}+1$$

Convert 1 to fraction \frac{10}{10}.

$$-\frac{19}{10}+\frac{10}{10}$$

Since -\frac{19}{10} and \frac{10}{10} have the same denominator, add them by adding their numerators.

$$\frac{-19+10}{10}$$

Add -19 and 10 to get -9.

$$-\frac{9}{10}$$

Factor

$$-0.9$$