Solve -4(y+1)+6y=2(y+2)-8

$$- 4 ( y + 1 ) + 6 y = 2 ( y + 2 ) - 8$$

Solve for y (complex solution)

$$y\in \mathrm{C}$$

Solution Steps

Use the distributive property to multiply -4 by y+1.

$$-4y-4+6y=2\left(y+2\right)-8$$

Combine -4y and 6y to get 2y.

$$2y-4=2\left(y+2\right)-8$$

Use the distributive property to multiply 2 by y+2.

$$2y-4=2y+4-8$$

Subtract 8 from 4 to get -4.

$$2y-4=2y-4$$

Subtract 2y from both sides.

$$2y-4-2y=-4$$

Combine 2y and -2y to get 0.

$$-4=-4$$

Compare -4 and -4.

$$\text{true}$$

This is true for any y.

$$y\in \mathrm{C}$$

Solve for y

$$y\in \mathrm{R}$$

Solution Steps

Use the distributive property to multiply -4 by y+1.

$$-4y-4+6y=2\left(y+2\right)-8$$

Combine -4y and 6y to get 2y.

$$2y-4=2\left(y+2\right)-8$$

Use the distributive property to multiply 2 by y+2.

$$2y-4=2y+4-8$$

Subtract 8 from 4 to get -4.

$$2y-4=2y-4$$

Subtract 2y from both sides.

$$2y-4-2y=-4$$

Combine 2y and -2y to get 0.

$$-4=-4$$

Compare -4 and -4.

$$\text{true}$$

This is true for any y.

$$y\in \mathrm{R}$$