Solve for a
a=\frac{9b+c+69}{2}
Solve for b
b=\frac{2a}{9}-\frac{c}{9}-\frac{23}{3}
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77-2a+9b+c=8
Add -4 and 81 to get 77.
-2a+9b+c=8-77
Subtract 77 from both sides.
-2a+9b+c=-69
Subtract 77 from 8 to get -69.
-2a+c=-69-9b
Subtract 9b from both sides.
-2a=-69-9b-c
Subtract c from both sides.
-2a=-9b-c-69
The equation is in standard form.
\frac{-2a}{-2}=\frac{-9b-c-69}{-2}
Divide both sides by -2.
a=\frac{-9b-c-69}{-2}
Dividing by -2 undoes the multiplication by -2.
a=\frac{9b+c+69}{2}
Divide -69-9b-c by -2.
77-2a+9b+c=8
Add -4 and 81 to get 77.
-2a+9b+c=8-77
Subtract 77 from both sides.
-2a+9b+c=-69
Subtract 77 from 8 to get -69.
9b+c=-69+2a
Add 2a to both sides.
9b=-69+2a-c
Subtract c from both sides.
9b=2a-c-69
The equation is in standard form.
\frac{9b}{9}=\frac{2a-c-69}{9}
Divide both sides by 9.
b=\frac{2a-c-69}{9}
Dividing by 9 undoes the multiplication by 9.
b=\frac{2a}{9}-\frac{c}{9}-\frac{23}{3}
Divide -69+2a-c by 9.
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