Solve -36x^2-3ax=0

$$- 36 x ^ { 2 } - 3 a x = 0$$

Solve for a (complex solution)

$$\left\{\begin{matrix}\\a=-12x\text{, }&\text{unconditionally}\\a\in \mathrm{C}\text{, }&x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Add 36x^{2} to both sides. Anything plus zero gives itself.

$$-3ax=36x^{2}$$

The equation is in standard form.

$$\left(-3x\right)a=36x^{2}$$

Divide both sides by -3x.

$$\frac{\left(-3x\right)a}{-3x}=\frac{36x^{2}}{-3x}$$

Dividing by -3x undoes the multiplication by -3x.

$$a=\frac{36x^{2}}{-3x}$$

Divide 36x^{2} by -3x.

$$a=-12x$$

Solve for a

$$\left\{\begin{matrix}\\a=-12x\text{, }&\text{unconditionally}\\a\in \mathrm{R}\text{, }&x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Add 36x^{2} to both sides. Anything plus zero gives itself.

$$-3ax=36x^{2}$$

The equation is in standard form.

$$\left(-3x\right)a=36x^{2}$$

Divide both sides by -3x.

$$\frac{\left(-3x\right)a}{-3x}=\frac{36x^{2}}{-3x}$$

Dividing by -3x undoes the multiplication by -3x.

$$a=\frac{36x^{2}}{-3x}$$

Divide 36x^{2} by -3x.

$$a=-12x$$

Solve for x

$$x=-\frac{a}{12}$$

$$x=0$$