Solve for x
x=\frac{8-y}{3}
Solve for y
y=8-3x
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-3x=-8+y
Add y to both sides.
-3x=y-8
The equation is in standard form.
\frac{-3x}{-3}=\frac{y-8}{-3}
Divide both sides by -3.
x=\frac{y-8}{-3}
Dividing by -3 undoes the multiplication by -3.
x=\frac{8-y}{3}
Divide -8+y by -3.
-y=-8+3x
Add 3x to both sides.
-y=3x-8
The equation is in standard form.
\frac{-y}{-1}=\frac{3x-8}{-1}
Divide both sides by -1.
y=\frac{3x-8}{-1}
Dividing by -1 undoes the multiplication by -1.
y=8-3x
Divide -8+3x by -1.
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