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-3x-\frac{1}{2}x-\frac{1}{3}=4x+10
To find the opposite of \frac{1}{2}x+\frac{1}{3}, find the opposite of each term.
-\frac{7}{2}x-\frac{1}{3}=4x+10
Combine -3x and -\frac{1}{2}x to get -\frac{7}{2}x.
-\frac{7}{2}x-\frac{1}{3}-4x=10
Subtract 4x from both sides.
-\frac{15}{2}x-\frac{1}{3}=10
Combine -\frac{7}{2}x and -4x to get -\frac{15}{2}x.
-\frac{15}{2}x=10+\frac{1}{3}
Add \frac{1}{3} to both sides.
-\frac{15}{2}x=\frac{30}{3}+\frac{1}{3}
Convert 10 to fraction \frac{30}{3}.
-\frac{15}{2}x=\frac{30+1}{3}
Since \frac{30}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.
-\frac{15}{2}x=\frac{31}{3}
Add 30 and 1 to get 31.
x=\frac{31}{3}\left(-\frac{2}{15}\right)
Multiply both sides by -\frac{2}{15}, the reciprocal of -\frac{15}{2}.
x=\frac{31\left(-2\right)}{3\times 15}
Multiply \frac{31}{3} times -\frac{2}{15} by multiplying numerator times numerator and denominator times denominator.
x=\frac{-62}{45}
Do the multiplications in the fraction \frac{31\left(-2\right)}{3\times 15}.
x=-\frac{62}{45}
Fraction \frac{-62}{45} can be rewritten as -\frac{62}{45} by extracting the negative sign.