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-3x^{2}=-75
Subtract 75 from both sides. Anything subtracted from zero gives its negation.
x^{2}=\frac{-75}{-3}
Divide both sides by -3.
x^{2}=25
Divide -75 by -3 to get 25.
x=5 x=-5
Take the square root of both sides of the equation.
-3x^{2}+75=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\left(-3\right)\times 75}}{2\left(-3\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -3 for a, 0 for b, and 75 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-3\right)\times 75}}{2\left(-3\right)}
Square 0.
x=\frac{0±\sqrt{12\times 75}}{2\left(-3\right)}
Multiply -4 times -3.
x=\frac{0±\sqrt{900}}{2\left(-3\right)}
Multiply 12 times 75.
x=\frac{0±30}{2\left(-3\right)}
Take the square root of 900.
x=\frac{0±30}{-6}
Multiply 2 times -3.
x=-5
Now solve the equation x=\frac{0±30}{-6} when ± is plus. Divide 30 by -6.
x=5
Now solve the equation x=\frac{0±30}{-6} when ± is minus. Divide -30 by -6.
x=-5 x=5
The equation is now solved.