Solve for x
x=\frac{7y-2}{3}
Solve for y
y=\frac{3x+2}{7}
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-3x=2-7y
Subtract 7y from both sides.
\frac{-3x}{-3}=\frac{2-7y}{-3}
Divide both sides by -3.
x=\frac{2-7y}{-3}
Dividing by -3 undoes the multiplication by -3.
x=\frac{7y-2}{3}
Divide 2-7y by -3.
7y=2+3x
Add 3x to both sides.
7y=3x+2
The equation is in standard form.
\frac{7y}{7}=\frac{3x+2}{7}
Divide both sides by 7.
y=\frac{3x+2}{7}
Dividing by 7 undoes the multiplication by 7.
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