Solve for c
c=\frac{3\left(x-1\right)}{2}
Solve for x
x=\frac{2c}{3}+1
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2c=-3+3x
Add 3x to both sides.
2c=3x-3
The equation is in standard form.
\frac{2c}{2}=\frac{3x-3}{2}
Divide both sides by 2.
c=\frac{3x-3}{2}
Dividing by 2 undoes the multiplication by 2.
-3x=-3-2c
Subtract 2c from both sides.
-3x=-2c-3
The equation is in standard form.
\frac{-3x}{-3}=\frac{-2c-3}{-3}
Divide both sides by -3.
x=\frac{-2c-3}{-3}
Dividing by -3 undoes the multiplication by -3.
x=\frac{2c}{3}+1
Divide -3-2c by -3.
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