Solve -3u+2-u^2-5+3u+2u^2-3

$$- 3 u + 2 - u ^ { 2 } - 5 + 3 u + 2 u ^ { 2 } - 3$$

Evaluate

$$u^{2}-6$$

Solution Steps

Subtract 5 from 2 to get -3.

$$-3u-3-u^{2}+3u+2u^{2}-3$$

Combine -3u and 3u to get 0.

$$-3-u^{2}+2u^{2}-3$$

Combine -u^{2} and 2u^{2} to get u^{2}.

$$-3+u^{2}-3$$

Subtract 3 from -3 to get -6.

$$-6+u^{2}$$

Differentiate w.r.t. u

$$2u$$

Steps Using Derivative Rule for Sum

Subtract 5 from 2 to get -3.

$$\frac{\mathrm{d}}{\mathrm{d}u}(-3u-3-u^{2}+3u+2u^{2}-3)$$

Combine -3u and 3u to get 0.

$$\frac{\mathrm{d}}{\mathrm{d}u}(-3-u^{2}+2u^{2}-3)$$

Combine -u^{2} and 2u^{2} to get u^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}u}(-3+u^{2}-3)$$

Subtract 3 from -3 to get -6.

$$\frac{\mathrm{d}}{\mathrm{d}u}(-6+u^{2})$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$2u^{2-1}$$

Subtract 1 from 2.

$$2u^{1}$$

For any term t, t^{1}=t.

$$2u$$