Solve -3b-1%>-24

$$- 3 b - 1 \% > - 24$$

Solve for b

$$b<\frac{2399}{300}$$

Solution Steps

Add \frac{1}{100} to both sides.

$$-3b>-24+\frac{1}{100}$$

Convert -24 to fraction -\frac{2400}{100}.

$$-3b>-\frac{2400}{100}+\frac{1}{100}$$

Since -\frac{2400}{100} and \frac{1}{100} have the same denominator, add them by adding their numerators.

$$-3b>\frac{-2400+1}{100}$$

Add -2400 and 1 to get -2399.

$$-3b>-\frac{2399}{100}$$

Divide both sides by -3. Since -3 is negative, the inequality direction is changed.

$$b<\frac{-\frac{2399}{100}}{-3}$$

Express \frac{-\frac{2399}{100}}{-3} as a single fraction.

$$b<\frac{-2399}{100\left(-3\right)}$$

Multiply 100 and -3 to get -300.

$$b<\frac{-2399}{-300}$$

Fraction \frac{-2399}{-300} can be simplified to \frac{2399}{300} by removing the negative sign from both the numerator and the denominator.

$$b<\frac{2399}{300}$$