Solve -3-1{-4+3(-4)-2[-2-6]+15div-3}

$$- 3 - 1 \{ - 4 + 3 ( - 4 ) - 2 [ - 2 - 6 ] + 15 \div - 3 \}$$

Evaluate

$$2$$

Solution Steps

Multiply 3 and -4 to get -12.

$$-3-1\left(-4-12-2\left(-2-6\right)+\frac{15}{-3}\right)$$

Subtract 12 from -4 to get -16.

$$-3-1\left(-16-2\left(-2-6\right)+\frac{15}{-3}\right)$$

Subtract 6 from -2 to get -8.

$$-3-1\left(-16-2\left(-8\right)+\frac{15}{-3}\right)$$

Multiply 2 and -8 to get -16.

$$-3-1\left(-16-\left(-16\right)+\frac{15}{-3}\right)$$

The opposite of -16 is 16.

$$-3-1\left(-16+16+\frac{15}{-3}\right)$$

Add -16 and 16 to get 0.

$$-3-1\left(0+\frac{15}{-3}\right)$$

Divide 15 by -3 to get -5.

$$-3-1\left(0-5\right)$$

Subtract 5 from 0 to get -5.

$$-3-1\left(-5\right)$$

Multiply 1 and -5 to get -5.

$$-3-\left(-5\right)$$

The opposite of -5 is 5.

$$-3+5$$

Add -3 and 5 to get 2.

$$2$$

Factor

$$2$$