Solve -3(u+2)+39>5(3-u)

$$- 3 ( u + 2 ) + 39 > 5 ( 3 - u )$$

Solve for u

$$u>-9$$

Solution Steps

Use the distributive property to multiply -3 by u+2.

$$-3u-6+39>5\left(3-u\right)$$

Add -6 and 39 to get 33.

$$-3u+33>5\left(3-u\right)$$

Use the distributive property to multiply 5 by 3-u.

$$-3u+33>15-5u$$

Add 5u to both sides.

$$-3u+33+5u>15$$

Combine -3u and 5u to get 2u.

$$2u+33>15$$

Subtract 33 from both sides.

$$2u>15-33$$

Subtract 33 from 15 to get -18.

$$2u>-18$$

Divide both sides by 2. Since 2 is positive, the inequality direction remains the same.

$$u>\frac{-18}{2}$$

Divide -18 by 2 to get -9.

$$u>-9$$