Solve -3*(-2)^0*(-2)^3-15:(-3)^1+sqrt{-1+17}-22=

$$- 3 \cdot ( - 2 ) ^ { 0 } \cdot ( - 2 ) ^ { 3 } - 15 : ( - 3 ) ^ { 1 } + \sqrt { - 1 + 17 } - 22 =$$

Evaluate

$$11$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 0 and 3 to get 3.

$$-3\left(-2\right)^{3}-\frac{15}{\left(-3\right)^{1}}+\sqrt{-1+17}-22$$

Calculate -2 to the power of 3 and get -8.

$$-3\left(-8\right)-\frac{15}{\left(-3\right)^{1}}+\sqrt{-1+17}-22$$

Multiply -3 and -8 to get 24.

$$24-\frac{15}{\left(-3\right)^{1}}+\sqrt{-1+17}-22$$

Calculate -3 to the power of 1 and get -3.

$$24-\frac{15}{-3}+\sqrt{-1+17}-22$$

Divide 15 by -3 to get -5.

$$24-\left(-5\right)+\sqrt{-1+17}-22$$

The opposite of -5 is 5.

$$24+5+\sqrt{-1+17}-22$$

Add 24 and 5 to get 29.

$$29+\sqrt{-1+17}-22$$

Add -1 and 17 to get 16.

$$29+\sqrt{16}-22$$

Calculate the square root of 16 and get 4.

$$29+4-22$$

Add 29 and 4 to get 33.

$$33-22$$

Subtract 22 from 33 to get 11.

$$11$$

Factor

$$11$$