Solve -3{(1-2)sqrt{25}+2^3+[6-3(6)+3(-4)]}

$$- 3 \{ ( 1 - 2 ) \sqrt { 25 } + 2 ^ { 3 } + [ 6 - 3 ( 6 ) + 3 ( - 4 ) ] \}$$

Evaluate

$$63$$

Solution Steps

Subtract 2 from 1 to get -1.

$$-3\left(-\sqrt{25}+2^{3}+6-3\times 6+3\left(-4\right)\right)$$

Calculate the square root of 25 and get 5.

$$-3\left(-5+2^{3}+6-3\times 6+3\left(-4\right)\right)$$

Calculate 2 to the power of 3 and get 8.

$$-3\left(-5+8+6-3\times 6+3\left(-4\right)\right)$$

Add -5 and 8 to get 3.

$$-3\left(3+6-3\times 6+3\left(-4\right)\right)$$

Multiply 3 and 6 to get 18.

$$-3\left(3+6-18+3\left(-4\right)\right)$$

Subtract 18 from 6 to get -12.

$$-3\left(3-12+3\left(-4\right)\right)$$

Subtract 12 from 3 to get -9.

$$-3\left(-9+3\left(-4\right)\right)$$

Multiply 3 and -4 to get -12.

$$-3\left(-9-12\right)$$

Subtract 12 from -9 to get -21.

$$-3\left(-21\right)$$

Multiply -3 and -21 to get 63.

$$63$$

Factor

$$3^{2}\times 7$$