Solve -3^4div21/3*(-2/3)^2

$$- 3 ^ { 4 } \div 2 \frac { 1 } { 3 } \times ( - \frac { 2 } { 3 } ) ^ { 2 }$$

Evaluate

$$-\frac{108}{7}\approx -15.428571429$$

Solution Steps

Calculate 3 to the power of 4 and get 81.

$$\frac{-81}{\frac{2\times 3+1}{3}}\left(-\frac{2}{3}\right)^{2}$$

Multiply 2 and 3 to get 6.

$$\frac{-81}{\frac{6+1}{3}}\left(-\frac{2}{3}\right)^{2}$$

Add 6 and 1 to get 7.

$$\frac{-81}{\frac{7}{3}}\left(-\frac{2}{3}\right)^{2}$$

Divide -81 by \frac{7}{3} by multiplying -81 by the reciprocal of \frac{7}{3}.

$$-81\times \frac{3}{7}\left(-\frac{2}{3}\right)^{2}$$

Express -81\times \frac{3}{7} as a single fraction.

$$\frac{-81\times 3}{7}\left(-\frac{2}{3}\right)^{2}$$

Multiply -81 and 3 to get -243.

$$\frac{-243}{7}\left(-\frac{2}{3}\right)^{2}$$

Fraction \frac{-243}{7} can be rewritten as -\frac{243}{7} by extracting the negative sign.

$$-\frac{243}{7}\left(-\frac{2}{3}\right)^{2}$$

Calculate -\frac{2}{3} to the power of 2 and get \frac{4}{9}.

$$-\frac{243}{7}\times \frac{4}{9}$$

Multiply -\frac{243}{7} times \frac{4}{9} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-243\times 4}{7\times 9}$$

Do the multiplications in the fraction \frac{-243\times 4}{7\times 9}.

$$\frac{-972}{63}$$

Reduce the fraction \frac{-972}{63} to lowest terms by extracting and canceling out 9.

$$-\frac{108}{7}$$

Factor

$$-\frac{108}{7} = -15\frac{3}{7} = -15.428571428571429$$