Solve -3^2-|-5^2|*(-2/5)^2-18+|-(-3)^2|

$$- 3 ^ { 2 } - | - 5 ^ { 2 } | \times ( - \frac { 2 } { 5 } ) ^ { 2 } - 18 + | - ( - 3 ) ^ { 2 } |$$

Evaluate

$$-22$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$-9-|-5^{2}|\left(-\frac{2}{5}\right)^{2}-18+|-\left(-3\right)^{2}|$$

Calculate 5 to the power of 2 and get 25.

$$-9-|-25|\left(-\frac{2}{5}\right)^{2}-18+|-\left(-3\right)^{2}|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -25 is 25.

$$-9-25\left(-\frac{2}{5}\right)^{2}-18+|-\left(-3\right)^{2}|$$

Calculate -\frac{2}{5} to the power of 2 and get \frac{4}{25}.

$$-9-25\times \frac{4}{25}-18+|-\left(-3\right)^{2}|$$

Cancel out 25 and 25.

$$-9-4-18+|-\left(-3\right)^{2}|$$

Subtract 4 from -9 to get -13.

$$-13-18+|-\left(-3\right)^{2}|$$

Subtract 18 from -13 to get -31.

$$-31+|-\left(-3\right)^{2}|$$

Calculate -3 to the power of 2 and get 9.

$$-31+|-9|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -9 is 9.

$$-31+9$$

Add -31 and 9 to get -22.

$$-22$$

Factor

$$-22$$