Solve -3^2*(-3^3)*(-3^-4)*(-3^-5)=

$$- 3 ^ { 2 } \cdot ( - 3 ^ { 3 } ) \cdot ( - 3 ^ { - 4 } ) \cdot ( - 3 ^ { - 5 } ) =$$

Evaluate

$$\frac{1}{81}\approx 0.012345679$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$-9\left(-3^{3}\right)\left(-3^{-4}\right)\left(-3^{-5}\right)$$

Calculate 3 to the power of 3 and get 27.

$$-9\left(-27\right)\left(-3^{-4}\right)\left(-3^{-5}\right)$$

Multiply -9 and -27 to get 243.

$$243\left(-3^{-4}\right)\left(-3^{-5}\right)$$

Calculate 3 to the power of -4 and get \frac{1}{81}.

$$243\left(-\frac{1}{81}\right)\left(-3^{-5}\right)$$

Multiply 243 and -\frac{1}{81} to get -3.

$$-3\left(-3^{-5}\right)$$

Calculate 3 to the power of -5 and get \frac{1}{243}.

$$-3\left(-\frac{1}{243}\right)$$

Multiply -3 and -\frac{1}{243} to get \frac{1}{81}.

$$\frac{1}{81}$$

Factor

$$\frac{1}{3 ^ {4}} = 0.012345679012345678$$