Solve -3^2+50div2^2*(-1/5)-1=

$$- 3 ^ { 2 } + 50 \div 2 ^ { 2 } \times ( - \frac { 1 } { 5 } ) - 1 =$$

Evaluate

$$-\frac{25}{2}=-12.5$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$-9+\frac{50}{2^{2}}\left(-\frac{1}{5}\right)-1$$

Calculate 2 to the power of 2 and get 4.

$$-9+\frac{50}{4}\left(-\frac{1}{5}\right)-1$$

Reduce the fraction \frac{50}{4} to lowest terms by extracting and canceling out 2.

$$-9+\frac{25}{2}\left(-\frac{1}{5}\right)-1$$

Multiply \frac{25}{2} times -\frac{1}{5} by multiplying numerator times numerator and denominator times denominator.

$$-9+\frac{25\left(-1\right)}{2\times 5}-1$$

Do the multiplications in the fraction \frac{25\left(-1\right)}{2\times 5}.

$$-9+\frac{-25}{10}-1$$

Reduce the fraction \frac{-25}{10} to lowest terms by extracting and canceling out 5.

$$-9-\frac{5}{2}-1$$

Convert -9 to fraction -\frac{18}{2}.

$$-\frac{18}{2}-\frac{5}{2}-1$$

Since -\frac{18}{2} and \frac{5}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-18-5}{2}-1$$

Subtract 5 from -18 to get -23.

$$-\frac{23}{2}-1$$

Convert 1 to fraction \frac{2}{2}.

$$-\frac{23}{2}-\frac{2}{2}$$

Since -\frac{23}{2} and \frac{2}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-23-2}{2}$$

Subtract 2 from -23 to get -25.

$$-\frac{25}{2}$$

Factor

$$-\frac{25}{2} = -12\frac{1}{2} = -12.5$$