Solve -3=a*(-3)+c

$$- 3 = a \cdot ( - 3 ) + c$$

Solve for a

$$a=\frac{c+3}{3}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$a\left(-3\right)+c=-3$$

Subtract c from both sides.

$$a\left(-3\right)=-3-c$$

The equation is in standard form.

$$-3a=-c-3$$

Divide both sides by -3.

$$\frac{-3a}{-3}=\frac{-c-3}{-3}$$

Dividing by -3 undoes the multiplication by -3.

$$a=\frac{-c-3}{-3}$$

Divide -3-c by -3.

$$a=\frac{c}{3}+1$$

Solve for c

$$c=3\left(a-1\right)$$

Solution Steps

Swap sides so that all variable terms are on the left hand side.

$$a\left(-3\right)+c=-3$$

Subtract a\left(-3\right) from both sides.

$$c=-3-a\left(-3\right)$$

Multiply -1 and -3 to get 3.

$$c=-3+3a$$