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-\frac{3}{5}x+7+\frac{4}{3}x=\frac{32}{3}
Add \frac{4}{3}x to both sides.
\frac{11}{15}x+7=\frac{32}{3}
Combine -\frac{3}{5}x and \frac{4}{3}x to get \frac{11}{15}x.
\frac{11}{15}x=\frac{32}{3}-7
Subtract 7 from both sides.
\frac{11}{15}x=\frac{32}{3}-\frac{21}{3}
Convert 7 to fraction \frac{21}{3}.
\frac{11}{15}x=\frac{32-21}{3}
Since \frac{32}{3} and \frac{21}{3} have the same denominator, subtract them by subtracting their numerators.
\frac{11}{15}x=\frac{11}{3}
Subtract 21 from 32 to get 11.
x=\frac{11}{3}\times \frac{15}{11}
Multiply both sides by \frac{15}{11}, the reciprocal of \frac{11}{15}.
x=\frac{11\times 15}{3\times 11}
Multiply \frac{11}{3} times \frac{15}{11} by multiplying numerator times numerator and denominator times denominator.
x=\frac{15}{3}
Cancel out 11 in both numerator and denominator.
x=5
Divide 15 by 3 to get 5.