Solve -2y_{3}-1=3-y/2

$$- 2 y _ { 3 } - 1 = \frac { 3 - y } { 2 }$$

Solve for y

$$y=4y_{3}+5$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2.

$$-4y_{3}-2=3-y$$

Swap sides so that all variable terms are on the left hand side.

$$3-y=-4y_{3}-2$$

Subtract 3 from both sides.

$$-y=-4y_{3}-2-3$$

Subtract 3 from -2 to get -5.

$$-y=-4y_{3}-5$$

Divide both sides by -1.

$$\frac{-y}{-1}=\frac{-4y_{3}-5}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$y=\frac{-4y_{3}-5}{-1}$$

Divide -4y_{3}-5 by -1.

$$y=4y_{3}+5$$

Solve for y_3

$$y_{3}=\frac{y-5}{4}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2.

$$-4y_{3}-2=3-y$$

Add 2 to both sides.

$$-4y_{3}=3-y+2$$

Add 3 and 2 to get 5.

$$-4y_{3}=5-y$$

Divide both sides by -4.

$$\frac{-4y_{3}}{-4}=\frac{5-y}{-4}$$

Dividing by -4 undoes the multiplication by -4.

$$y_{3}=\frac{5-y}{-4}$$

Divide 5-y by -4.

$$y_{3}=\frac{y-5}{4}$$