Solve -2x^2-2x+2-9/x

$$- 2 x ^ { 2 } - 2 x + 2 - \frac { 9 } { x }$$

Evaluate

$$-2x^{2}-2x+2-\frac{9}{x}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply -2x^{2}-2x+2 times \frac{x}{x}.

$$\frac{\left(-2x^{2}-2x+2\right)x}{x}-\frac{9}{x}$$

Since \frac{\left(-2x^{2}-2x+2\right)x}{x} and \frac{9}{x} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\left(-2x^{2}-2x+2\right)x-9}{x}$$

Do the multiplications in \left(-2x^{2}-2x+2\right)x-9.

$$\frac{-2x^{3}-2x^{2}+2x-9}{x}$$

Factor

$$-\frac{2x^{3}+2x^{2}-2x+9}{x}$$