Solve for x
x=\frac{3y-13}{2}
Solve for y
y=\frac{2x+13}{3}
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-2x=13-3y
Subtract 3y from both sides.
\frac{-2x}{-2}=\frac{13-3y}{-2}
Divide both sides by -2.
x=\frac{13-3y}{-2}
Dividing by -2 undoes the multiplication by -2.
x=\frac{3y-13}{2}
Divide 13-3y by -2.
3y=13+2x
Add 2x to both sides.
3y=2x+13
The equation is in standard form.
\frac{3y}{3}=\frac{2x+13}{3}
Divide both sides by 3.
y=\frac{2x+13}{3}
Dividing by 3 undoes the multiplication by 3.
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