Solve for x
x=\frac{3y}{2}+2z-\frac{29}{2}
Solve for y
y=\frac{2x-4z+29}{3}
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-2x+4z=29-3y
Subtract 3y from both sides.
-2x=29-3y-4z
Subtract 4z from both sides.
-2x=29-4z-3y
The equation is in standard form.
\frac{-2x}{-2}=\frac{29-4z-3y}{-2}
Divide both sides by -2.
x=\frac{29-4z-3y}{-2}
Dividing by -2 undoes the multiplication by -2.
x=\frac{3y}{2}+2z-\frac{29}{2}
Divide 29-3y-4z by -2.
3y+4z=29+2x
Add 2x to both sides.
3y=29+2x-4z
Subtract 4z from both sides.
3y=2x-4z+29
The equation is in standard form.
\frac{3y}{3}=\frac{2x-4z+29}{3}
Divide both sides by 3.
y=\frac{2x-4z+29}{3}
Dividing by 3 undoes the multiplication by 3.
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