Solve -2b*3a*(-3ab)

$$- 2 b \times 3 a \times ( - 3 a b )$$

Evaluate

$$18\left(ab\right)^{2}$$

Solution Steps

Multiply b and b to get b^{2}.

$$-2b^{2}\times 3a\left(-3\right)a$$

Multiply a and a to get a^{2}.

$$-2b^{2}\times 3a^{2}\left(-3\right)$$

Multiply -2 and 3 to get -6.

$$-6b^{2}a^{2}\left(-3\right)$$

Multiply -6 and -3 to get 18.

$$18b^{2}a^{2}$$

Differentiate w.r.t. b

$$36ba^{2}$$