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a\left(-2a+16\right)=0
Factor out a.
a=0 a=8
To find equation solutions, solve a=0 and -2a+16=0.
-2a^{2}+16a=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
a=\frac{-16±\sqrt{16^{2}}}{2\left(-2\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -2 for a, 16 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
a=\frac{-16±16}{2\left(-2\right)}
Take the square root of 16^{2}.
a=\frac{-16±16}{-4}
Multiply 2 times -2.
a=\frac{0}{-4}
Now solve the equation a=\frac{-16±16}{-4} when ± is plus. Add -16 to 16.
a=0
Divide 0 by -4.
a=-\frac{32}{-4}
Now solve the equation a=\frac{-16±16}{-4} when ± is minus. Subtract 16 from -16.
a=8
Divide -32 by -4.
a=0 a=8
The equation is now solved.
-2a^{2}+16a=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
\frac{-2a^{2}+16a}{-2}=\frac{0}{-2}
Divide both sides by -2.
a^{2}+\frac{16}{-2}a=\frac{0}{-2}
Dividing by -2 undoes the multiplication by -2.
a^{2}-8a=\frac{0}{-2}
Divide 16 by -2.
a^{2}-8a=0
Divide 0 by -2.
a^{2}-8a+\left(-4\right)^{2}=\left(-4\right)^{2}
Divide -8, the coefficient of the x term, by 2 to get -4. Then add the square of -4 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
a^{2}-8a+16=16
Square -4.
\left(a-4\right)^{2}=16
Factor a^{2}-8a+16. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(a-4\right)^{2}}=\sqrt{16}
Take the square root of both sides of the equation.
a-4=4 a-4=-4
Simplify.
a=8 a=0
Add 4 to both sides of the equation.