Solve -2-2x-2+4x-5

$$- 2 - 2 x - 2 + 4 x - 5$$

Evaluate

$$2x-9$$

Solution Steps

Subtract 2 from -2 to get -4.

$$-4-2x+4x-5$$

Combine -2x and 4x to get 2x.

$$-4+2x-5$$

Subtract 5 from -4 to get -9.

$$-9+2x$$

Differentiate w.r.t. x

$$2$$

Steps Using Derivative Rule for Sum

Subtract 2 from -2 to get -4.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-4-2x+4x-5)$$

Combine -2x and 4x to get 2x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-4+2x-5)$$

Subtract 5 from -4 to get -9.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-9+2x)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$2x^{1-1}$$

Subtract 1 from 1.

$$2x^{0}$$

For any term t except 0, t^{0}=1.

$$2\times 1$$

For any term t, t\times 1=t and 1t=t.

$$2$$