Solve -2(2)^4+6(2)^3-3(2)^2+4(2)

$$- 2 ( 2 ) ^ { 4 } + 6 ( 2 ) ^ { 3 } - 3 ( 2 ) ^ { 2 } + 4 ( 2 )$$

Evaluate

$$12$$

Solution Steps

Calculate 2 to the power of 4 and get 16.

$$-2\times 16+6\times 2^{3}-3\times 2^{2}+4\times 2$$

Multiply -2 and 16 to get -32.

$$-32+6\times 2^{3}-3\times 2^{2}+4\times 2$$

Calculate 2 to the power of 3 and get 8.

$$-32+6\times 8-3\times 2^{2}+4\times 2$$

Multiply 6 and 8 to get 48.

$$-32+48-3\times 2^{2}+4\times 2$$

Add -32 and 48 to get 16.

$$16-3\times 2^{2}+4\times 2$$

Calculate 2 to the power of 2 and get 4.

$$16-3\times 4+4\times 2$$

Multiply 3 and 4 to get 12.

$$16-12+4\times 2$$

Subtract 12 from 16 to get 4.

$$4+4\times 2$$

Multiply 4 and 2 to get 8.

$$4+8$$

Add 4 and 8 to get 12.

$$12$$

Factor

$$2^{2}\times 3$$