Solve -21/3+31/4-41/5

$$- 2 \frac { 1 } { 3 } + 3 \frac { 1 } { 4 } - 4 \frac { 1 } { 5 }$$

Evaluate

$$-\frac{197}{60}\approx -3.283333333$$

Solution Steps

Multiply 2 and 3 to get 6.

$$-\frac{6+1}{3}+\frac{3\times 4+1}{4}-\frac{4\times 5+1}{5}$$

Add 6 and 1 to get 7.

$$-\frac{7}{3}+\frac{3\times 4+1}{4}-\frac{4\times 5+1}{5}$$

Multiply 3 and 4 to get 12.

$$-\frac{7}{3}+\frac{12+1}{4}-\frac{4\times 5+1}{5}$$

Add 12 and 1 to get 13.

$$-\frac{7}{3}+\frac{13}{4}-\frac{4\times 5+1}{5}$$

Least common multiple of 3 and 4 is 12. Convert -\frac{7}{3} and \frac{13}{4} to fractions with denominator 12.

$$-\frac{28}{12}+\frac{39}{12}-\frac{4\times 5+1}{5}$$

Since -\frac{28}{12} and \frac{39}{12} have the same denominator, add them by adding their numerators.

$$\frac{-28+39}{12}-\frac{4\times 5+1}{5}$$

Add -28 and 39 to get 11.

$$\frac{11}{12}-\frac{4\times 5+1}{5}$$

Multiply 4 and 5 to get 20.

$$\frac{11}{12}-\frac{20+1}{5}$$

Add 20 and 1 to get 21.

$$\frac{11}{12}-\frac{21}{5}$$

Least common multiple of 12 and 5 is 60. Convert \frac{11}{12} and \frac{21}{5} to fractions with denominator 60.

$$\frac{55}{60}-\frac{252}{60}$$

Since \frac{55}{60} and \frac{252}{60} have the same denominator, subtract them by subtracting their numerators.

$$\frac{55-252}{60}$$

Subtract 252 from 55 to get -197.

$$-\frac{197}{60}$$

Factor

$$-\frac{197}{60} = -3\frac{17}{60} = -3.283333333333333$$