Solve -2^2+|-9|-(-4)^2*(-1/2)^3

$$- 2 ^ { 2 } + | - 9 | - ( - 4 ) ^ { 2 } \times ( - \frac { 1 } { 2 } ) ^ { 3 }$$

Evaluate

$$7$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$-4+|-9|-\left(-4\right)^{2}\left(-\frac{1}{2}\right)^{3}$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -9 is 9.

$$-4+9-\left(-4\right)^{2}\left(-\frac{1}{2}\right)^{3}$$

Add -4 and 9 to get 5.

$$5-\left(-4\right)^{2}\left(-\frac{1}{2}\right)^{3}$$

Calculate -4 to the power of 2 and get 16.

$$5-16\left(-\frac{1}{2}\right)^{3}$$

Calculate -\frac{1}{2} to the power of 3 and get -\frac{1}{8}.

$$5-16\left(-\frac{1}{8}\right)$$

Express 16\left(-\frac{1}{8}\right) as a single fraction.

$$5-\frac{16\left(-1\right)}{8}$$

Multiply 16 and -1 to get -16.

$$5-\frac{-16}{8}$$

Divide -16 by 8 to get -2.

$$5-\left(-2\right)$$

The opposite of -2 is 2.

$$5+2$$

Add 5 and 2 to get 7.

$$7$$

Factor

$$7$$