Solve for x
x=\frac{3\left(y-6\right)}{2}
Solve for y
y=\frac{2\left(x+9\right)}{3}
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-\frac{2}{3}x=6-y
Subtract y from both sides.
\frac{-\frac{2}{3}x}{-\frac{2}{3}}=\frac{6-y}{-\frac{2}{3}}
Divide both sides of the equation by -\frac{2}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.
x=\frac{6-y}{-\frac{2}{3}}
Dividing by -\frac{2}{3} undoes the multiplication by -\frac{2}{3}.
x=\frac{3y}{2}-9
Divide 6-y by -\frac{2}{3} by multiplying 6-y by the reciprocal of -\frac{2}{3}.
y=6+\frac{2}{3}x
Add \frac{2}{3}x to both sides.
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