Solve -18=4/5x-12+b

$$- 18 = \frac { 4 } { 5 } x - 12 + b$$

Solve for b

$$b=-\frac{4x}{5}-6$$

Solution Steps

Swap sides so that all variable terms are on the left hand side.

$$\frac{4}{5}x-12+b=-18$$

Subtract \frac{4}{5}x from both sides.

$$-12+b=-18-\frac{4}{5}x$$

Add 12 to both sides.

$$b=-18-\frac{4}{5}x+12$$

Add -18 and 12 to get -6.

$$b=-6-\frac{4}{5}x$$

Solve for x

$$x=-\frac{5b}{4}-\frac{15}{2}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$\frac{4}{5}x-12+b=-18$$

Add 12 to both sides.

$$\frac{4}{5}x+b=-18+12$$

Add -18 and 12 to get -6.

$$\frac{4}{5}x+b=-6$$

Subtract b from both sides.

$$\frac{4}{5}x=-6-b$$

The equation is in standard form.

$$\frac{4}{5}x=-b-6$$

Divide both sides of the equation by \frac{4}{5}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{4}{5}x}{\frac{4}{5}}=\frac{-b-6}{\frac{4}{5}}$$

Dividing by \frac{4}{5} undoes the multiplication by \frac{4}{5}.

$$x=\frac{-b-6}{\frac{4}{5}}$$

Divide -6-b by \frac{4}{5} by multiplying -6-b by the reciprocal of \frac{4}{5}.

$$x=-\frac{5b}{4}-\frac{15}{2}$$